You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin.
Input: amount = 5, coins = [1, 2, 5] Output: 4 Explanation: there are four ways to make up the amount: 5=5 5=2+2+1 5=2+1+1+1 5=1+1+1+1+1
Input: amount = 3, coins = [2] Output: 0 Explanation: the amount of 3 cannot be made up just with coins of 2.
Input: amount = 10, coins = [10] Output: 1
You can assume that
- 0 <= amount <= 5000
- 1 <= coin <= 5000
- the number of coins is less than 500
- the answer is guaranteed to fit into signed 32-bit integer
implSolution{pubfnchange(amount:i32,coins:Vec<i32>) -> i32{letmut dp = vec![0; amount asusize + 1]; dp[0] = 1;for&coin in&coins {for i in(coin asusize)..=(amount asusize){ dp[i] += dp[i - coin asusize];}} dp[amount asusize]}}